Torna al Thread

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click '---- qui carico da una dir di esempio i file jpeg Dim dirInfo As New DirectoryInfo("C:\Users\Matteo\Pictures") DataGridView1.DataSource = dirInfo.GetFiles("*.jpg") DataGridView1.Columns.Insert(0, New MiaColonnaImmagine()) End Sub Private Class MiaColonnaImmagine Inherits DataGridViewImageColumn Public Overrides Property CellTemplate() As System.Windows.Forms.DataGridViewCell Get Return New MiaCellaImmagine() '----- qui gli dico che uso la mia classe che dara' un valore diverso dallo standard End Get Set(ByVal value As System.Windows.Forms.DataGridViewCell) MyBase.CellTemplate = value End Set End Property End Class Private Class MiaCellaImmagine Inherits DataGridViewImageCell Protected Overrides Function GetFormattedValue(ByVal value As Object, ByVal rowIndex As Integer, ByRef cellStyle As System.Windows.Forms.DataGridViewCellStyle, ByVal valueTypeConverter As System.ComponentModel.TypeConverter, ByVal formattedValueTypeConverter As System.ComponentModel.TypeConverter, ByVal context As System.Windows.Forms.DataGridViewDataErrorContexts) As Object '----- nel tuo caso avrai gia' i record pronti con il path, qui invece vado a prendermi un FileInfo perche' avevo bindato quello alla griglia Dim file As FileInfo = Me.DataGridView.Rows(rowIndex).DataBoundItem If file Is Nothing Then Return Nothing Else Return Image.FromFile(file.FullName) '---- torno l'immagine letta dal path, tanto la colonna è cmq di tipo immagine End If End Function End Class
Copyright © dotNetHell.it 2002-2024
Running on Windows Server 2008 R2 Standard, SQL Server 2012 & ASP.NET 3.5